If we consider as a minimal
quantity of time, the time Tmin in which the light would cover distance equal
with length = 6,626026 x10^{34} or would acquire the minimal
quantity of energy h▪ 1Hz then we find :
2,997924
x10^{8} m in
1
sec
6,62606
x10^{34} m what sec ?
Tmin = λ / c = 2,210216 x 10^{42} →
Tmin x c = h = λmin
If Tmin = 2,210216 x 10^{42}
then
fmax = 1/Tmin = 0,452444 x10^{42}
The time Tmin in which the light
would cover distance equal with length h= 6,626026 x10^{34} m or
would acquire the minimal quantity of energy h▪ 1Hz is Tmin = λmin/c
gives a frequency fmax = 0,452444 x10^{42} Hz.
Example with the length
λ=0,24263 x10^{11} m of the electron: In how much time t the light
would cover distance of length λe = 0,24263 x10^{11}
m.
Answer: Time t= 1 x λe/c
= 0,0809326 x10^{19} sec = 1/fe . It's ok.
Reminder: The constant length that is
contained in the constant speed of light c is a length S=2,997924 x10^{8}
m. This length via the 2pi gives a radius r. That is to
say 2,997924 x10^{8} m / 6,283185 = 0,4771344 x10^{8} m. This
radius rc
= 0,4771344 x10^{8} m divided with the quantity hbar as an elementary
length of radius gives us a ratio 0,4771344 x10^{8} / 1,0545715 x10^{34}
= 0,452444 x10^{42} .
Also, with the logic that the quantity
h/2π
is an elementary radius r that when it divides the biggest speed of light c
(c/hbar)
gives us result an angular velocity ω .The angular
velocity ω/2π
= frequency f.
With the logic of
this observation it results again as length of wave λ
the constant action h and as a biggest frequency fmax =
0,452444 x10^{42} Hz.
The same frequency fmax =
0,452444 x10^{42} Hz results from the magnetic penetrability
μο =12,56636 x10^{7} Henry /m and dielectric constant
εo= 8,854 x10^{12} Farad /m of empty
(free) space, when we consider that the constant Plank h coincides with a
fundamental length λmin = 6,62606 x10^{34}
m
and applying relation
V_{c} =1/ √μο εο
and the main type of coordination in the electrotechnics
T= 2π √L C :
μο λ_{min}
= 83,265508 x10^{41 }Henry
εο λ_{min}
= 58,667135 x 10^{46} Farad
(83,26550 x1041
) (58,66713 x1046
)=4884,95 x10^{87} (Henry x Farad = sec^{2} )
√4,88495
x10^{84} = 2,2102 x 10^{42} sec
and 1/2,2102 x 10^{42} =
0,45244 x10^{42} Hz
For the type T= 2π √L C we consider that
length λ_{min} = h_{bar} 2pi
NEW LIMITS result with the
scenario that constant h it is also length of wave λ.
The limits fmax, Emax, Mmax, Tmin are suspect very near the maximum limits
which result from the mass and the energy Planck, the constant of unified constants Mpl
= √ h c /G (Mpl
≈ 5,45624 x10^{8} kg). λ_{min} /
λ_{planck} = 16,3574
