Mpl = √(h c / G) 

Mpl c² = Eplanck

Eplanck / h = 7,4008 x10⁴² Hz

c / hbar =ωmax → ω / 2π = fmax

fmax = 0,452444 x10⁴² Hz

h fmax = Ec → Ec / h =  c / λmin

f_pl = 7,4008 x10⁴² Hz

E_pl = 49,038293 x10⁸ J

M_pl = 5,456246 x10^-8 kg

E_min = h = 6,62606 x10^-34

M_min = h/c² = 0,73725 x10^-50

λ_pl = c / f_pl = 0,405080 x10^-34

a_pl = f_pl² λ_pl = c² /λ_pl = 22,186977 x10⁵⁰ m/s²

f_c = 0,452444 x10⁴² Hz

E_c = 2,997924 x10⁸ (kg m² /s ?)

M_c = 0,3335641 x10^-8 = M_pl /16,3574

E_min = λ_c = 6,62606 x10^-34

M_min = 1/E_c f_c = M_c/f_c = 0,73725 x10^-50

λ_c = h

a_max = f_c² λ_c = c² /λ_c = 1,356391 x10⁵⁰ m/s²

ΕΦΑΡΜΟΓΗ ΜΕ ΤΑ ΣΤΟΙΧΕΙΑ ΤΟΥ ΗΛΕΚΤΡΟΝΙΟΥ

ΕΦΑΡΜΟΓΗ ΜΕ ΤΑ ΣΤΟΙΧΕΙΑ ΤΟΥ ΗΛΕΚΤΡΟΝΙΟΥ

E_pl / E_e = 0,598969 x10²³ = M_pl / M_e

E_e / h = 12,35592 x 10¹⁹ = M_e / M_min

fe↑ x fe↓ = fpl = 7,4008 x10⁴² Hz

fe↑ / fe↓ ~ 50

c / 0,598969 x10²³ = 5,00514 x10^-15 = V_e

c / 12,35592 x 10¹⁹ = 0,242630 x10^-11

λe↑ x λe↓ = 1,2143 x10^-26

λe↑ / λe↓ = 0,02 ≈ c G

E_pl / 12,35592 x 10¹⁹ = 3,968809 x10^-11

E_e / 0,598969 x10²³ = 136,6867 x10^-38

ΔΗΛΑΔΗ:

c E_e / E_pl = V_e = c M_e / M_pl

Για να βρούμε το 5,005 x10^-15 με τo λ_e² :

1,214363 x10^-26 / 0,24263 x10^-11

M_pl / M_c = 16,3574

E_pl / E_c = 16,3574

h / 0,405080 x10^-34 = 16,3574

h / 16,3574 = 0,405080 x10^-34 = λ_pl

16,3574 x 0,452444 x10⁴² =7,4008 x10⁴² =f_pl

=(f_e)

=f_e↓

=(λ1)

=λ_e↓

E_c / E_e = 0,0366176 x10²³ = M_c / M_e

E_e / λ_c = 12,35592 x10¹⁹ = M_e / M_min

fe x fe↓ = fc = 0,452444 x10⁴²

fe / fe↓ = 0,00296 x10⁴

c / 0,0366176 x10²³ = 81,871122 x10^-15

c / 12,35592 x 10¹⁹ = 0,242630 x10^-11

λe x λe↓ = h c = 19,8644 x10^-26

λe / λe↓ = 337,431 x10^-4

Για να βρούμε το 5,005 x10^-15 με την f_e :

0,18327 x10⁸ / 0,0366176 x10²³ = 5,0049 x10^-15 = V_e 

(0,0366176 x10²³ ) x (5,00514 x10^-15 )=0,18327 x10⁸

c / 0,18327 x10⁸ =16,3579636

c / 16,3579636 = 0,18327 x10⁸

E_e / 16,3579636 = 5,0049 x10^-15 = V_e

0,18327 x10⁸ / c = 0,0611323

1 / 16,3579636 = 0,0611323

16,3579636 / c = 1 / 0,18327 x10⁸ = Mpl

Ec / 12,35592 x10¹⁹ = 0,24263 x10^-11 (λ_e')

Ee / 0,0366176 x10²³ = 2235,8401 x10^-38

ή  0,223584 x10^-34

λe↑ x λe↓ = h c →

→ h=λe↑ x λe↓ / c → c =λe↑ x λe↓ / h

=(f_e)

=f_e↓

=(λ)

=λ_e↓

Em / 16,3579636 = M c / Mpl = h / Mpl λm = V_E

Για να δίνει ταχύτητα η διαίρεση της ενέργειας, ο αριθμός 16,357 πρέπει να έχει διαστάσεις ορμής,

όπως το h •1Hz / c = 2,210216 x10^-42

16,3579 / 2,210216 x10^-42 = fplanck